Why tanx isn't Continuous on [0, pi/2] | Calculus 1 Exercises
We discuss the continuity of tanx and see why tanx is not continuous on the closed interval [0,2pi] but is continuous on the half-closed interval [0,2pi). Since tanx=sinx/cosx and cosx=0 at pi/2, we see that tanx is undefined and has a vertical asymptote at x=pi/2. #calculus1 #apcalculus
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