How to check whether a number is Armstrong or not in Python | Armstrong Number Program in Python
This is a Python Program to check if a number is an Armstrong number.
Problem Description
The program takes a number and checks if it is an Armstrong number.
Problem Solution
1. Take in an integer and store it in a variable.
2. Convert each digit of the number to a string variable and store it in a list.
3. Then cube each of the digits and store it in another list.
4. Find the sum of the cube of digits in the list and check if it is equal to the original number.
5. Print the final result.
6. Exit.
Program/Source Code
Here is source code of the Python Program to check if a number is an Armstrong number. The program output is also shown below.
n=int(input("Enter any number: "))
a=list(map(int,str(n)))
b=list(map(lambda x:x**3,a))
if(sum(b)==n):
print("The number is an armstrong number. ")
else:
print("The number isn't an arsmtrong number. ")
Program Explanation
1. User must enter the number and store it in a variable.
2. The map function obtains each digit from the number and converts it to a string and stores it in a list.
3. The second map function cubes each digit and stores it in another list.
4. Then the sum of the cubes of the digits is found and is checked if it is equal to the original number.
5. If the sum of the cube of digits is equal to the original number, the number is an Armstrong number.
6. The final result is printed.
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