A connected graph of order n has at least n-1 edges, in other words - tree graphs are the minimally connected graphs. We'll be proving this result in today's graph theory lesson!
We'll be using a special type of contradiction proof called a proof by minimum counterexample. If we assume that there is a graph contradicting our claim, we can consider one such graph of minimum order, then we will show that this "minimum order counterexample" is actually not a minimum order counterexample, producing a contradiction and proving our claim.
Connected graphs with one less edge than vertices NEVER have cycles, and connected graphs with no cycles are called tree graphs; check out these lesson on them...
Intro to Tree Graphs: • Intro to Tree Graphs | Trees in Graph...
Proof that a tree graph of order n has size n-1: • Proof: Tree Graph of Order n Has Size...
Proof that a connected graph with n vertices and n-1 edges is a tree graph: • Proof: Graph with n Vertices and n-1 ...
◆ Donate on PayPal: https://www.paypal.me/wrathofmath
◆ Support Wrath of Math on Patreon: / wrathofmathlessons
I hope you find this video helpful, and be sure to ask any questions down in the comments!
+WRATH OF MATH+
Follow Wrath of Math on...
● Instagram: / wrathofmathedu
● Facebook: / wrathofmath
● Twitter: / wrathofmathedu
My Music Channel: / seanemusic
Watch video Proof: Connected Graph of Order n Has at least n-1 Edges | Graph Theory online without registration, duration hours minute second in high quality. This video was added by user Wrath of Math 31 July 2020, don't forget to share it with your friends and acquaintances, it has been viewed on our site 18,468 once and liked it 230 people.