In this video we'll discuss an important result in lattice geometry: All primitive lattice triangles have and area of 1/2. Incidentally, the method of proof shows that all primitive lattice parallelograms have an area of 1.
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References and Notes:
Ref. 1 This proof is entirely based on Garbett (2010) - https://documents.kenyon.edu/math/Gar...
Ref 2. This video shows how the determinant of a matrix gives the scaling of an area under that matrix transform - • The determinant | Chapter 6, Essence ...
Note 1. If (m+i,n+j) was not a visible point, then this would imply that there was a lattice point within one of the primitive triangles: a contradiction.
Note 2. Assume the image of the parallelogram was not primitive. There would be a lattice point in it's interior or on the boundary. Since the determinant of the matrix is 1, we can use the inverse of the matrix to give the original parallelogram. However, since points on or within the boundary remain so under the transform, this would imply the original parallelogram was not primitive: a contradiction.
Note 3. An interval [x,x+1] on the real line always contains an integer.
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