NCERT Solutions For Class 6 Maths Chapter 5 Understanding Elementary Shapes
September 10, 2019 by phani
NCERT Solutions For Class 6 Maths Chapter 5 Understanding Elementary Shapes Ex 5.1
Free download NCERT Solutions for Class 6 Maths Chapter 5 Exercise 5.1, Ex 5.2, Ex 5.3, Ex 5.4, Ex 5.5, Ex 5.6 and Ex 5.7, 5.8 and 5.9 Understanding Elementary Shapes PDF for CBSE 2020 Exams.
You can also Download NCERT Solutions for Class 6 Maths to help you to revise complete Syllabus and score more marks in your examinations.
Understanding Elementary Shapes Class 6 Ex 5.1
Understanding Elementary Shapes Class 6 Ex 5.2
Understanding Elementary Shapes Class 6 Ex 5.3
Understanding Elementary Shapes Class 6 Ex 5.4
Understanding Elementary Shapes Class 6 Ex 5.5
Understanding Elementary Shapes Class 6 Ex 5.6
Understanding Elementary Shapes Class 6 Ex 5.7
Understanding Elementary Shapes Class 6 Ex 5.8
Understanding Elementary Shapes Class 6 Ex 5.9
Understanding Elementary Shapes Class 6 Extra Questions
Understanding Elementary Shapes Class 6 Ex 5.1
Ex 5.1 Class 6 Maths Question 1.
What is the disadvantage in comparing line segment by metre observation?
Solution:
Comparing the lengths of two line segments simply by ‘observation’ may not be accurate. So we use divider to compare the length of the given line segments.
Ex 5.1 Class 6 Maths Question 2.
Why is it better to use a divider than a ruler, while measuring the length of a line segment?
Solution:
Measuring the length of a line segment using a ruler, we may have the following errors:
(i) Thickness of the ruler
(ii) Angular viewing
These errors can be eradicated by using the divider. So, it is better to use a divider than a ruler, while measuring the length of a line segment.
Ex 5.1 Class 6 Maths Question 3.
Draw any line segment, say AB¯¯¯¯¯¯¯¯. Take any point C lying in between A and B. Measure the lengths of AB, BC and AC. Is AB = AC + CB?
[Note: If A, B, C are any three points on a line such AC + CB = AB, then we can be sure that C lies between A and B]
Solution:
Let us consider

A, B and C such that C lies between A and B and AB = 7 cm.
AC = 3 cm, CB = 4 cm.
∴ AC + CB = 3 cm + 4 cm = 7 cm.
But, AB = 7 cm.
So, AB = AC + CB.
Ex 5.1 Class 6 Maths Question 4.
If A, B, C are three points on a line such that AB = 5 cm, BC = 3 cm and AC = 8 cm, which one of them lies between the other two?
Solution:
We have, AB = 5 cm; BC = 3 cm
∴ AB + BC = 5 + 3 = 8 cm
But, AC = 8 cm
Hence, B lies between A and C.
Ex 5.1 Class 6 Maths Question 5.
Verify, whether D is the mid point of AG¯¯¯¯¯¯¯¯ .

Solution:
From the given figure, we have
AG = 7 cm – 1 cm = 6 cm
AD = 4 cm – 1 cm = 3 cm
and DG = 7 cm – 4 cm = 3 cm
∴ AG = AD + DG.
Hence, D is the mid point of AG¯¯¯¯¯¯¯¯.
Ex 5.1 Class 6 Maths Question 6.
If B is the mid point of AC¯¯¯¯¯¯¯¯ and C is the mid point of BD¯¯¯¯¯¯¯¯ , where A, B, C, D lie on a straight line, say why AB = CD?
Solution:
We have

B is the mid point of AC¯¯¯¯¯¯¯¯ .
∴ AB = BC …(i)
C is the mid-point of BD¯¯¯¯¯¯¯¯ .
BC = CD
From Eq.(i) and (ii), We have
AB = CD

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