a geometric AM-GM derivation

Published: 05 April 2023
on channel: Dr Peyam
3,513
272

a geometric AM-GM derivation. We prove the arithmetic-geometric mean inequality by comparing areas of triangles. This generalizes to higher dimensions with boxes, although I'm not sure of the proof. AM GM says that the geometric mean sqrt ab is always less than or equal to the arithmetic mean a+b/2

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